# 3 Different Ways to Solve Cubic Equations Easily

How to Solve a Cubic Equation Problem?

24 Jan, 2019
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When you are assigned with a cubic equation problem in your assignment by your maths professor, then it may look unsolvable for you in the beginning. However, the easy ways for solving it has been already introduced hundreds of years ago. We know that finding the solution is a bit difficult, but with the right approach, even the most complex and trickiest cubic equation can be solved easily. Here are a few strategies to tackle with it.
Way 1: Solve It with Quadratic Formula
Cubic equation are in the form of ax3+bx2+cx+d=0
If you see that the equation is not in standard form, then do the basic arithmetic calculations to get the cubic equation.
On the other hand, if the equation contains a constant, then you need to follow a different approach.
Divide the Equation with an X
Since your equation has an X variable in it, one X can be factored out in the form of:
X(ax2+bx+c)
Use the Quadratic Formula to Solve it
The obtained equation is in quadratic form. This means that now you can easily find the values of a, b, and c just by placing them in the quadratic formula, i.e.,

Way 2: Finding Solutions with Integers
The way maintained above is quite convenient because you don’t have to implement any new mathematical formula or trick. But, it won’t help you with all the cubic equations.
Like, if your equation has a non-zero value for d, then you need to follow the step mentioned below.
Example: 2×3+5×2+15x+6=0
In this the value of d is 6, so you can’t implement the above method.
Here you have to find the factors of a and d
A=2=2*1
D=6=6*1, 3*2
Factors of a=1,2 and of d=1,2,3,6.
Divide the factors of a by d
The next step is to make a list of the values that you get after dividing each factor of a by each factor of d.
1,1/2,1/3,1/6 and 2,1,2/3,3
Next, add the negatives to it
-1,-1/2,-1/3,-1/6 and -2,-1,-2/3,-3